Art of Problem Solving
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2002 AMC 8 Problems/Problem 11: Difference between revisions

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== Problem 11 ==
A sequence of squares is made of identical square tiles. The edge of each square is one tile length longer than the edge of the previous square. The first three squares are shown. How many more tiles does the seventh square require than the sixth?
A sequence of squares is made of identical square tiles. The edge of each square is one tile length longer than the edge of the previous square. The first three squares are shown. How many more tiles does the seventh square require than the sixth?



Revision as of 19:35, 28 July 2011

Problem 11

A sequence of squares is made of identical square tiles. The edge of each square is one tile length longer than the edge of the previous square. The first three squares are shown. How many more tiles does the seventh square require than the sixth?


$\text{(A)}\ 11\qquad\text{(B)}\ 12\qquad\text{(C)}\ 13\qquad\text{(D)}\ 14\qquad\text{(E)}\ 15$

Solution