1999 AHSME Problems/Problem 3: Difference between revisions

Revision as of 12:49, 8 June 2011

To find the number halfway between $\frac{1}{8}$ and $\frac{1}{10}$ , simply take the arithmetic mean, which is

$\frac{\frac{1}{8}+\frac{1}{10}}{2}=\frac{\frac{9}{40}}{2}=\frac{9}{80}.$

Thus the answer is choice $\boxed{E}.$

1999 AHSME (Problems • Answer Key • Resources)
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