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2008 AMC 12B Problems/Problem 13: Difference between revisions

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\textbf{(D)}\ \frac{3-\sqrt3}{9} \qquad
\textbf{(D)}\ \frac{3-\sqrt3}{9} \qquad
\textbf{(E)}\ \frac{\sqrt3}{12}</math>
\textbf{(E)}\ \frac{\sqrt3}{12}</math>
==See Also==
{{AMC12 box|year=2008|ab=B|num-b=12|num-a=14}}

Revision as of 12:34, 30 May 2011

This problem needs a solution. If you have a solution for it, please help us out by adding it.

Problem

Vertex $E$ of equilateral $\triangle{ABC}$ is in the interior of unit square $ABCD$. Let $R$ be the region consisting of all points inside $ABCD$ and outside $\triangle{ABC}$ whose distance from $AD$ is between $\frac{1}{3}$ and $\frac{2}{3}$. What is the area of $R$?

$\textbf{(A)}\ \frac{12-5\sqrt3}{72} \qquad \textbf{(B)}\ \frac{12-5\sqrt3}{36} \qquad \textbf{(C)}\ \frac{\sqrt3}{18} \qquad \textbf{(D)}\ \frac{3-\sqrt3}{9} \qquad \textbf{(E)}\ \frac{\sqrt3}{12}$

See Also

2008 AMC 12B (Problems • Answer Key • Resources)
Preceded by
Problem 12 		Followed by
Problem 14
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 12 Problems and Solutions
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