Art of Problem Solving

2011 AIME II Problems/Problem 2: Difference between revisions

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Drawing the square and examining the given lengths, you find that the three segments cut the square into three equal horizontal sections (I dont know how to make a diagram so somebody please insert one)
Drawing the square and examining the given lengths, you find that the three segments cut the square into three equal horizontal sections (I dont know how to make a diagram so somebody please insert one)
Therefore, (x being the side length), <math>sqrt(x^2+(x/3)^2)=900</math>.
Therefore, (x being the side length), <math>squareroot(x^2+(x/3)^2)=900</math>.

Revision as of 21:26, 30 March 2011

Problem:

On square ABCD, point E lies on side AD and point F lies on side BC, so that BE=EF=FD=30. Find the area of the square ABCD.


Solution:

Drawing the square and examining the given lengths, you find that the three segments cut the square into three equal horizontal sections (I dont know how to make a diagram so somebody please insert one) Therefore, (x being the side length), $squareroot(x^2+(x/3)^2)=900$.