Angle Bisector Theorem: Difference between revisions

Revision as of 14:46, 21 June 2006

The Angle Bisector Theorem states that given triangle $\triangle ABC$ and angle bisector AX, where X is on side BC, then $AC/CX = AB/BX$ .

Revision as of 14:43, 21 June 2006 view source Rrusczyk (talk \| contribs) Bureaucrats, editor, Administrators 410 edits removed ambiguities, added link ← Older edit		Revision as of 14:46, 21 June 2006 view source Rrusczyk (talk \| contribs) Bureaucrats, editor, Administrators 410 edits removed ambiguities/added links. Newer edit →
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	The '''Angle Bisector Theorem''' states that given [[triangle]] <math>\triangle ABC</math> and [[angle bisector]] AX, where X is on side BC, then <math>~~\frac{~~AC}{CX}=~~\frac{~~AB}{BX}</math>.		The '''Angle Bisector Theorem''' states that given [[triangle]] <math>\triangle ABC</math> and [[angle bisector]] AX, where X is on side BC, then <math>AC/CX = AB/BX</math>.