Art of Problem Solving

2010 AMC 10B Problems/Problem 13: Difference between revisions

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== Solution ==
== Solution ==
$Case 1: 2x-|60-2x|=x
<math>Case 1: 2x-|60-2x|=x</math>

Revision as of 20:02, 24 January 2011

Problem

What is the sum of all the solutions of $x = \left|2x-|60-2x|\right|$?

$\mathrm{(A)}\ 32 \qquad \mathrm{(B)}\ 60 \qquad \mathrm{(C)}\ 92 \qquad \mathrm{(D)}\ 120 \qquad \mathrm{(E)}\ 124$

Solution

$Case 1: 2x-|60-2x|=x$