2005 AMC 12B Problems/Problem 4: Difference between revisions
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== Solution == | == Solution == | ||
Lisa's goal was to get an A on <math>80\% \cdot 50 = 40</math> quizzes. She already has A's on <math>22</math> quizzes, so she needs to get A's on <math>40-22=18</math> more. There are <math>50-30=20</math> quizzes left, so she can afford to get less than an A on <math>20-18=\boxed{2}</math> of them. | |||
== See also == | == See also == | ||
* [[2005 AMC 12B Problems]] | * [[2005 AMC 12B Problems]] | ||
Revision as of 21:17, 17 April 2009
Problem
At the beginning of the school year, Lisa's goal was to earn an A on at least 
of her 
quizzes for the year. She earned an A on 
of the first 
quizzes. If she is to achieve her goal, on at most how many of the remaining quizzes can she earn a grade lower than an A?
Solution
Lisa's goal was to get an A on 
quizzes. She already has A's on quizzes, so she needs to get A's on 
more. There are 
quizzes left, so she can afford to get less than an A on 
of them.
