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2005 AMC 12B Problems/Problem 1: Difference between revisions

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== Problem ==
== Problem ==
Two is <math>10\%</math> of <math>x</math> and <math>20\%</math> of <math>y</math>.  What is <math>x-y</math>?
A scout troop buys <math>1000</math> candy bars at a price of five for <math>2</math> dollars. They sell all the candy bars at the price of two for <math>1</math> dollar.  What was their profit, in dollars?


<math>
<math>
\mathrm{(A)}\ 1     \qquad
\mathrm{(A)}\ 100     \qquad
\mathrm{(B)}\ 2     \qquad
\mathrm{(B)}\ 200     \qquad
\mathrm{(C)}\ 5     \qquad
\mathrm{(C)}\ 300     \qquad
\mathrm{(D)}\ 10     \qquad
\mathrm{(D)}\ 400     \qquad
\mathrm{(E)}\ 20
\mathrm{(E)}\ 500
</math>
</math>


Revision as of 20:56, 17 April 2009

Problem

A scout troop buys $1000$ candy bars at a price of five for $2$ dollars. They sell all the candy bars at the price of two for $1$ dollar. What was their profit, in dollars?

$\mathrm{(A)}\ 100 \qquad \mathrm{(B)}\ 200 \qquad \mathrm{(C)}\ 300 \qquad \mathrm{(D)}\ 400 \qquad \mathrm{(E)}\ 500$

Solution

$2=0.1x \Rightarrow x=20$.

$2=0.2y \Rightarrow y=10$.

$\therefore x-y=20-10=\boxed{10}$.

See also

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