2009 AMC 10A Problems/Problem 1: Difference between revisions
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== Problem | == Problem == | ||
One can holds <math>12</math> ounces of soda. What is the minimum number of cans needed to provide a gallon (128 ounces) of soda? | One can holds <math>12</math> ounces of soda. What is the minimum number of cans needed to provide a gallon (<math>128</math> ounces) of soda? | ||
<math> | <math>\mathrm{(A)}\ 7\qquad | ||
\mathrm{(A)}\ 7 | \mathrm{(B)}\ 8\qquad | ||
\qquad | \mathrm{(C)}\ 9\qquad | ||
\mathrm{(B)}\ 8 | \mathrm{(D)}\ 10\qquad | ||
\qquad | \mathrm{(E)}\ 11</math> | ||
\mathrm{(C)}\ 9 | |||
\qquad | == Solution == | ||
\mathrm{(D)}\ 10 | <math>10</math> cans would hold <math>120</math> ounces, but <math>128>120</math>, so <math>11</math> cans are required. Thus, the answer is <math>\mathrm{(E)}</math>. | ||
\qquad | |||
\mathrm{(E)}\ 11 | {{AMC10 box|year=2008|ab=A|before=First Question|num-a=2}} | ||
</math> | |||
Revision as of 13:46, 15 February 2009
Problem
One can holds 
ounces of soda. What is the minimum number of cans needed to provide a gallon (
ounces) of soda?
Solution
cans would hold 
ounces, but 
, so 
cans are required. Thus, the answer is 
.
| 2008 AMC 10A (Problems • Answer Key • Resources) | ||
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