2025 AMC 8 Problems/Problem 10: Difference between revisions
Mathcosine (talk | contribs) |
|||
| Line 25: | Line 25: | ||
==Video Solution by Thinking Feet== | ==Video Solution by Thinking Feet== | ||
https://youtu.be/PKMpTS6b988 | https://youtu.be/PKMpTS6b988 | ||
==Video Solution(Quick, fast, easy!)== | |||
https://youtu.be/fdG7EDW_7xk | |||
~MC | |||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2025|num-b=9|num-a=11}} | {{AMC8 box|year=2025|num-b=9|num-a=11}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 17:42, 9 March 2025
Problem
In the figure below, 
is a rectangle with sides of length 
inches and 
= 3 inches. Rectangle is rotated 
clockwise around the midpoint of side 
to give a second rectangle. What is the total area, in square inches, covered by the two overlapping rectangles?
Solution 1
The area of each rectangle is 
. Then the sum of the areas of the two regions is the sum of the areas of the two rectangles, minus the area of their overlap. To find the area of the overlap, we note that the region of overlap is a square, each of whose sides have length 
(as they are formed by the midpoint of one of the long sides and a vertex). Then the answer is 
.
~ cxsmi
~ Edited by Aoum
Video Solution by Cool Math Problems
https://youtu.be/BRnILzqVwHk?si=YIRjHgok5ifMsK_x&t=560
Video Solution 1 by SpreadTheMathLove
https://www.youtube.com/watch?v=jTTcscvcQmI
Video Solution (A Clever Explanation You’ll Get Instantly)
https://youtu.be/VP7g-s8akMY?si=geTr-OnL-4wC94XG&t=814 ~hsnacademy
Video Solution by Thinking Feet
Video Solution(Quick, fast, easy!)
~MC
See Also
| 2025 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 9 |
Followed by Problem 11 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing
