2011 AMC 8 Problems/Problem 2: Difference between revisions
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The area of a rectangle is given by the formula length times width. Karl's garden is <math>20 \times 45 = 900</math> square feet and Makenna's garden is <math>25 \times 40 = 1000</math> square feet. Since <math>1000 > 900,</math> Makenna's garden is larger by <math>1000-900=100</math> square feet. <math>\Rightarrow \boxed{ \textbf{(E)}\ \text{Makenna's garden is larger by 100 square feet.} }</math> | The area of a rectangle is given by the formula length times width. Karl's garden is <math>20 \times 45 = 900</math> square feet and Makenna's garden is <math>25 \times 40 = 1000</math> square feet. Since <math>1000 > 900,</math> Makenna's garden is larger by <math>1000-900=100</math> square feet. <math>\Rightarrow \boxed{ \textbf{(E)}\ \text{Makenna's garden is larger by 100 square feet.} }</math> | ||
==Video Solution by WhyMath== | |||
https://youtu.be/CzAPGrFs0xs | |||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2011|num-b=1|num-a=3}} | {{AMC8 box|year=2011|num-b=1|num-a=3}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 10:01, 18 November 2024
Problem
Karl's rectangular vegetable garden is
feet by
feet, and Makenna's is
feet by
feet. Whose garden is larger in area?
Solution
The area of a rectangle is given by the formula length times width. Karl's garden is
square feet and Makenna's garden is
square feet. Since
Makenna's garden is larger by
square feet.
Video Solution by WhyMath
See Also
| 2011 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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