Art of Problem Solving

2024 AMC 12B Problems/Problem 15: Difference between revisions

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Created page with "==Solution (Shoelace Theorem)== We rewrite: <math>A(0,1)</math> <math>B(\log _{2} 3, 2)</math> <math>C(\log _{2} 7, 3)</math> From here we setup Shoelace Theorem and obtain: <..."
 
Mendenhallisbald (talk | contribs)
Line 3: Line 3:
<math>A(0,1)</math>
<math>A(0,1)</math>
<math>B(\log _{2} 3, 2)</math>
<math>B(\log _{2} 3, 2)</math>
<math>C(\log _{2} 7, 3)</math>
<math>C(\log _{2} 7, 3)</math>.
 
From here we setup Shoelace Theorem and obtain:
From here we setup Shoelace Theorem and obtain:
<math>\frac{1}{2}(2(\log _{2} 3) - log _{2} 7)</math>
<math>\frac{1}{2}(2(\log _{2} 3) - log _{2} 7)</math>

Revision as of 00:59, 14 November 2024

Solution (Shoelace Theorem)

We rewrite: $A(0,1)$ $B(\log _{2} 3, 2)$ $C(\log _{2} 7, 3)$.

From here we setup Shoelace Theorem and obtain: $\frac{1}{2}(2(\log _{2} 3) - log _{2} 7)$ Following log properties and simplifying gives (B).

~PeterDoesPhysics