2024 AMC 12A Problems/Problem 7: Difference between revisions
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Someone please clean this up lol | Someone please clean this up lol | ||
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== Solution 5 (Complex Number) == | |||
~[https://artofproblemsolving.com/wiki/index.php/User:Cyantist luckuso] | |||
==See also== | ==See also== | ||
{{AMC12 box|year=2024|ab=A|num-b=6|num-a=8}} | {{AMC12 box|year=2024|ab=A|num-b=6|num-a=8}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 19:06, 9 November 2024
Problem
In
,
and
. Points
lie on hypotenuse
so that
. What is the length of the vector sum
Solution 1 (technical vector bash)
Let us find an expression for the
- and
-components of
. Note that
, so
. All of the vectors
and so on up to
are equal; moreover, they equal
.
We now note that
(
copies of
added together). Furthermore, note that
We want
's length, which can be determined from the
- and
-components. Note that the two values should actually be the same - in this problem, everything is symmetric with respect to the line
, so the magnitudes of the
- and
-components should be identical. The
-component is easier to calculate.
One can similarly evaulate the
-component and obtain an identical answer; thus, our desired length is
.
~Technodoggo
Solution 2
Notice that the average vector sum is 1. Multiplying the 2024 by 1, our answer is
~MC
Solution 3 (Pair Sum)
Let point
reflect over
We can see that for all
,
As a result,
~lptoggled image and edited by ~luckuso
Solution 4
Using Pythagoream theorom, we see the length of the hypotenuse is
. There are 2024 points on
, that are equal spaced, so there are 2025 line segments along that hypotenuse.
is the length of each line segment. We get
Someone please clean this up lol
~helpmebro
Solution 5 (Complex Number)
See also
| 2024 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 6 |
Followed by Problem 8 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
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