Art of Problem Solving

2003 AMC 8 Problems/Problem 2: Difference between revisions

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<math>\mathrm{(A)}\ 55 \qquad\mathrm{(B)}\ 57 \qquad\mathrm{(C)}\ 58 \qquad\mathrm{(D)}\ 59 \qquad\mathrm{(E)}\ 61</math>
<math>\mathrm{(A)}\ 55 \qquad\mathrm{(B)}\ 57 \qquad\mathrm{(C)}\ 58 \qquad\mathrm{(D)}\ 59 \qquad\mathrm{(E)}\ 61</math>
==Solution==
The smallest prime factor is <math> 2 </math>, and since <math> 58 </math> is the only multiple of <math> 2 </math>, the answer is <math> \boxed{\mathrm{(C)}\ 58} </math>.


== Video Solution by OmegaLearn ==
== Video Solution by OmegaLearn ==
Line 11: Line 14:
==Video Solution==
==Video Solution==
https://youtu.be/7an5wU9Q5hk?t=152
https://youtu.be/7an5wU9Q5hk?t=152
==Solution==
The smallest prime factor is <math> 2 </math>, and since <math> 58 </math> is the only multiple of <math> 2 </math>, the answer is <math> \boxed{\mathrm{(C)}\ 58} </math>.


==See Also==
==See Also==
{{AMC8 box|year=2003|num-b=1|num-a=3}}
{{AMC8 box|year=2003|num-b=1|num-a=3}}
{{MAA Notice}}
{{MAA Notice}}

Revision as of 00:42, 17 October 2024

Problem

Which of the following numbers has the smallest prime factor?

$\mathrm{(A)}\ 55 \qquad\mathrm{(B)}\ 57 \qquad\mathrm{(C)}\ 58 \qquad\mathrm{(D)}\ 59 \qquad\mathrm{(E)}\ 61$

Solution

The smallest prime factor is $2$, and since $58$ is the only multiple of $2$, the answer is $\boxed{\mathrm{(C)}\ 58}$.

Video Solution by OmegaLearn

https://youtu.be/7an5wU9Q5hk?t=152

~ pi_is_3.14

Video Solution

https://youtu.be/7an5wU9Q5hk?t=152

See Also

2003 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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