1985 AJHSME Problems/Problem 23: Difference between revisions
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==Solution 2 (Similar to above solution) == | ==Solution 2 (Similar to above solution) == | ||
Each teacher teaches <math>4</math> classes and each class has <math>30</math> students, so each teacher teaches <math>120</math> students in one class. | |||
So, to teach five classes, there has to be <math>5</math> teachers, but there is <math>1200</math> students, so multiply by <math>\frac{1200}{120}</math> which is <math>50</math>, or <math>\boxed{\textbf{(E)}\ 50}</math> | |||
==See Also== | ==See Also== | ||
Revision as of 18:16, 6 October 2024
Problem
King Middle School has 
students. Each student takes 
classes a day. Each teacher teaches 
classes. Each class has 
students and 
teacher. How many teachers are there at King Middle School?
Solution
If each student has classes, and there are students, then they have a total of 
classes among them.
Each class has students, so there must be 
classes. Each class has teacher, so the teachers have a total of 
classes among them.
Each teacher teaches classes, so if there are 
teachers, they have 
classes among them. This was found to be , so ![\[4t=200\Rightarrow t=50\]](http://latex.artofproblemsolving.com/4/5/f/45fcdd0d7945c7294b7071e3d42baca6ff32773e.png)
This is answer choice 
Solution 2 (Similar to above solution)
Each teacher teaches classes and each class has students, so each teacher teaches 
students in one class.
So, to teach five classes, there has to be teachers, but there is students, so multiply by 
which is 
, or 
See Also
| 1985 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 22 |
Followed by Problem 24 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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