2007 AMC 8 Problems/Problem 23: Difference between revisions
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== Solution 2 == | == Solution 2 == | ||
The pinwheel is composed of <math>8</math> obtuse triangles whose base measures length <math>1</math> and height measures length <math>1.5</math>. Using the area formula for triangles, the pinwheel has an area of | The pinwheel is composed of <math>8</math> congruent obtuse triangles whose base measures length <math>1</math> and height measures length <math>1.5</math>. Using the area formula for triangles, the pinwheel has an area of | ||
<cmath>8(\frac12\cdot1\cdot1.5)=8{0.75}=\boxed{\textbf{(B) 6}}.</cmath> | <cmath>8(\frac12\cdot1\cdot1.5)=8{0.75}=\boxed{\textbf{(B) 6}}.</cmath> | ||
Revision as of 22:27, 28 July 2024
Problem
What is the area of the shaded pinwheel shown in the 
grid?
![[asy] filldraw((2.5,2.5)--(0,1)--(1,1)--(1,0)--(2.5,2.5)--(4,0)--(4,1)--(5,1)--(2.5,2.5)--(5,4)--(4,4)--(4,5)--(2.5,2.5)--(1,5)--(1,4)--(0,4)--cycle, gray, black); int i; for(i=0; i<6; i=i+1) { draw((i,0)--(i,5)); draw((0,i)--(5,i)); } [/asy]](http://latex.artofproblemsolving.com/b/b/1/bb1fcead3fb785c17349c43a31ed1e90bfc319e0.png)
Solution 1
The area of the square around the pinwheel is 25. The area of the pinwheel is equal to 
Each of the four triangles have a base of 3 units and a height of 2.5 units, and so their combined area is 15 units squared. Then the unshaded space consists of the four triangles with total area of 15, and there are four white corner squares. Therefore the area of the pinwheel is 
which is 
Solution 2
The pinwheel is composed of 
congruent obtuse triangles whose base measures length 
and height measures length 
. Using the area formula for triangles, the pinwheel has an area of
![\[8(\frac12\cdot1\cdot1.5)=8{0.75}=\boxed{\textbf{(B) 6}}.\]](http://latex.artofproblemsolving.com/2/a/5/2a59e397b4d491b84f36206fb36be058ed35cdb1.png)
Video Solution
https://www.youtube.com/watch?v=dQw4w9WgXcQ -Happytwin
Video Solution by OmegaLearn
https://youtu.be/abSgjn4Qs34?t=748
~ pi_is_3.14
See Also
| 2007 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 22 |
Followed by Problem 24 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: Unable to save thumbnail to destination
