Median of a triangle: Difference between revisions
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Each triangle has <math>3</math> medians. The medians are [[concurrent]] at the [[centroid]]. The [[centroid]] divides the medians (segments) in a <math>2:1</math> ratio. | Each triangle has <math>3</math> medians. The medians are [[concurrent]] at the [[centroid]]. The [[centroid]] divides the medians (segments) in a <math>2:1</math> ratio. | ||
[[Stewart's Theorem]] applied to the case <math>m=n</math>, gives the length of the median to side <math>BC</math> equal to <center><math>\frac 12 \sqrt{2AB^2+2AC^2-BC^2}</math></center> This formula is particularly useful when <math>\angle CAB</math> is right, as by the Pythagorean Theorem we find that <math>BM=AM=CM</math>. | [[Stewart's Theorem]] applied to the case <math>m=n</math>, gives the length of the median to side <math>BC</math> equal to <center><math>\frac 12 \sqrt{2AB^2+2AC^2-BC^2}</math></center> This formula is particularly useful when <math>\angle CAB</math> is right, as by the Pythagorean Theorem we find that <math>BM=AM=CM</math>. This occurs when <math>M</math> is the circumcenter of <math>\triangle ABC.</math> | ||
== See Also == | == See Also == | ||
Latest revision as of 19:24, 6 March 2024
A median of a triangle is a cevian of the triangle that joins one vertex to the midpoint of the opposite side.
In the following figure,
is a median of triangle
.
Each triangle has
medians. The medians are concurrent at the centroid. The centroid divides the medians (segments) in a
ratio.
Stewart's Theorem applied to the case
, gives the length of the median to side
equal to
This formula is particularly useful when
is right, as by the Pythagorean Theorem we find that
. This occurs when
is the circumcenter of
See Also
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