2024 AMC 8 Problems/Problem 7: Difference between revisions
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==Problem== | ==Problem== | ||
A person is playing one turn in a card-based game. They can play Card A for 1 point, Card B for 2 points, and Card C for 3 points. If order of the cards doesn't matter, how many possible ways are there to play one turn | A person is playing one turn in a card-based game. They can play Card A for 1 point, Card B for 2 points, and Card C for 3 points. If order of the cards doesn't matter, how many possible ways are there to play one turn using up a total of 20 points considering that that there is an unlimited amount of each card? | ||
<math>\textbf{(A) } 21 \qquad \textbf{(B) } 37 \qquad \textbf{(C) } 43 \qquad \textbf{(D) } 44 \qquad \textbf{(E) } 259</math> | <math>\textbf{(A) } 21 \qquad \textbf{(B) } 37 \qquad \textbf{(C) } 43 \qquad \textbf{(D) } 44 \qquad \textbf{(E) } 259</math> | ||
Revision as of 18:28, 22 January 2024
Problem
A person is playing one turn in a card-based game. They can play Card A for 1 point, Card B for 2 points, and Card C for 3 points. If order of the cards doesn't matter, how many possible ways are there to play one turn using up a total of 20 points considering that that there is an unlimited amount of each card?
Note: This is not one of the AMC 8 2024 questions.
