Art of Problem Solving

1989 OIM Problems/Problem 2: Difference between revisions

Tomasdiaz (talk | contribs)
Created page with "== Problem == ~translated into English by Tomas Diaz. ~orders@tomasdiaz.com Let <math>a</math>, <math>b</math>, and <math>c</math> be the longitudes of the sides of a triangle..."
 
Tomasdiaz (talk | contribs)
No edit summary
Line 1: Line 1:
== Problem ==
== Problem ==
~translated into English by Tomas Diaz. ~orders@tomasdiaz.com
Let <math>a</math>, <math>b</math>, and <math>c</math> be the longitudes of the sides of a triangle.  Prove:
Let <math>a</math>, <math>b</math>, and <math>c</math> be the longitudes of the sides of a triangle.  Prove:
<cmath>\frac{a-b}{a+b}+\frac{b-c}{b+c}+\frac{c-a}{c+a}<\frac{1}{16}</cmath>
<cmath>\frac{a-b}{a+b}+\frac{b-c}{b+c}+\frac{c-a}{c+a}<\frac{1}{16}</cmath>
~translated into English by Tomas Diaz. ~orders@tomasdiaz.com


== Solution ==
== Solution ==
{{solution}}
{{solution}}

Revision as of 12:16, 13 December 2023

Problem

Let $a$, $b$, and $c$ be the longitudes of the sides of a triangle. Prove: \[\frac{a-b}{a+b}+\frac{b-c}{b+c}+\frac{c-a}{c+a}<\frac{1}{16}\]

~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.