Art of Problem Solving
Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

2023 AMC 10B Problems/Problem 2: Difference between revisions

← Older editNewer edit →
Rollover2020 (talk | contribs)
editor
7 edits
No edit summary
Mintylemon66 (talk | contribs)
editor
23 edits
No edit summary
Line 1: Line 1:
There are 2022 users on a social network called Mathbook, and some of them are Mathbook-friends. (On Mathbook, friendship is always mutual and permanent.)
==Problem==


Starting now, Mathbook will only allow a new friendship to be formed between two users if they have at least two friends in common. What is the minimum number of friendships that must already exist so that every user could eventually become friends with every other user?
Carlos went to a sports store to buy running shoes. Running shoes were on sale, with prices reduced by <math>20\% </math>on every pair of shoes. Carlos also knew that he had to pay a <math>7.5\%</math> sales tax on the discounted price. He had <math> \$43 </math> dollars. What is the original (before discount) price of the most expensive shoes he could afford to buy?  
 
 
<math>\textbf{(A) }\$46\qquad\textbf{(B) }\$47\qquad\textbf{(C) }\$48\qquad\textbf{(D) }\$49\qquad\textbf{(E) }\$50 </math>
==Solution==
 
Let the original price be <math>x</math> dollars.
After the discount, the price becomes <math> 80\%x</math> dollars.
After tax, the price becomes <math> 80\% \times (1+7.5\%) = 86\% x </math> dollars.
So, <math>43=86\%x</math>, <math>x=\boxed{\textbf{(E) }\$50}.</math>
 
 
 
~Mintylemon66

Revision as of 14:41, 15 November 2023

Problem

Carlos went to a sports store to buy running shoes. Running shoes were on sale, with prices reduced by $20\%$on every pair of shoes. Carlos also knew that he had to pay a $7.5\%$ sales tax on the discounted price. He had $\$43$ dollars. What is the original (before discount) price of the most expensive shoes he could afford to buy?


$\textbf{(A) }\$46\qquad\textbf{(B) }\$47\qquad\textbf{(C) }\$48\qquad\textbf{(D) }\$49\qquad\textbf{(E) }\$50$

Solution

Let the original price be $x$ dollars. After the discount, the price becomes $80\%x$ dollars. After tax, the price becomes $80\% \times (1+7.5\%) = 86\% x$ dollars. So, $43=86\%x$, $x=\boxed{\textbf{(E) }\$50}.$


~Mintylemon66

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=2023_AMC_10B_Problems/Problem_2&oldid=203097"