2023 AMC 10A Problems/Problem 6: Difference between revisions
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==Solution== | ==Solution== | ||
<math>\boxed{ | |||
Each of the vertices is counted <math>3</math> times because each vertex is shared by three different edges. | |||
Each of the edges is counted <math>2</math> times because each edge is shared by two different faces. | |||
Since the sum of the integers assigned to all vertices is <math>21</math>, the final answer is <math> 21\times3\times2=\boxed{(D)126}</math> | |||
~Mintylemon66 | |||
Revision as of 17:45, 9 November 2023
What is 1+1?
Solution
Each of the vertices is counted 
times because each vertex is shared by three different edges.
Each of the edges is counted 
times because each edge is shared by two different faces.
Since the sum of the integers assigned to all vertices is 
, the final answer is 
~Mintylemon66
