2008 AMC 8 Problems/Problem 13: Difference between revisions
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==Video Solution== | ==Video Solution== | ||
https://www.youtube.com/watch?v=LKhOV9p4WiY ~David | https://www.youtube.com/watch?v=LKhOV9p4WiY ~David | ||
==Solution== | ==Solution== | ||
Revision as of 16:13, 3 November 2023
Problem
Mr. Harman needs to know the combined weight in pounds of three boxes he wants to mail. However, the only available scale is not accurate for weights less than 
pounds or more than 
pounds. So the boxes are weighed in pairs in every possible way. The results are 
, 
and 
pounds. What is the combined weight in pounds of the three boxes?
Video Solution
https://www.youtube.com/watch?v=LKhOV9p4WiY ~David
Solution
Each box is weighed twice during this, so the combined weight of the three boxes is half the weight of these separate measures
![\[\frac{122+125+127}{2} = \frac{374}{2} = \boxed{\textbf{(C)}\ 187}.\]](http://latex.artofproblemsolving.com/2/0/c/20c6d8379377b5f2b3ec4a4e6155ba77b4a867d2.png)
See Also
| 2008 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 12 |
Followed by Problem 14 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: Unable to save thumbnail to destination
