2003 AIME II Problems/Problem 8: Difference between revisions
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== Problem == | == Problem == | ||
Find the eighth term of the sequence <math>1440,</math> <math>1716,</math> <math>1848,\ldots,</math> whose terms are formed by multiplying the corresponding terms of two arithmetic sequences. | |||
== Solution == | == Solution == | ||
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== See also == | == See also == | ||
{{AIME box|year=2003|n=II|num-b=7|num-a=9}} | |||
Revision as of 13:38, 21 November 2007
Problem
Find the eighth term of the sequence 
whose terms are formed by multiplying the corresponding terms of two arithmetic sequences.
Solution
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See also
| 2003 AIME II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
