1967 AHSME Problems/Problem 6: Difference between revisions

Latest revision as of 00:35, 16 August 2023

If $f(x)=4^x$ then $f(x+1)-f(x)$ equals:

$\text{(A)}\ 4\qquad\text{(B)}\ f(x)\qquad\text{(C)}\ 2f(x)\qquad\text{(D)}\ 3f(x)\qquad\text{(E)}\ 4f(x)$

The desired expression is equal to $4^{x+1} - 4^{x}$ Using the fact that $4^{x+1}$ = $4^{x}*4$ , we see that the answer is $3*4^{x}$ $\fbox{D}$

1967 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 5	Followed by Problem 7
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40
All AHSME Problems and Solutions

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 == See also ==
-{{AHSME box|year=1967|num-b=5|num-a=7}}
+{{AHSME 40p box|year=1967|num-b=5|num-a=7}}
 [[Category:Introductory Algebra Problems]]
 {{MAA Notice}}