2022 SSMO Speed Round Problems/Problem 1: Difference between revisions
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The expression then has the same last digit as | The expression then has the same last digit as | ||
<cmath>^2 + 2^{4} + 2^{2} + 2^{3} + 3^2 + 3^{4} + 3^{2} + 3^{3}</cmath> | |||
which is just <math>8</math>. | which is just <math>8</math>. | ||
Revision as of 12:41, 3 July 2023
Problem
Let
and
Find the last digit of
Solution
Since the power of
to an integer is always
, it
follows that we want to find the last digit of
\begin{align*}
&2^2 + 2^{20} + 2^{202} + 2^{2023} + \\
&3^2 + 3^{20} + 3^{202} + 3^{2023}
\end{align*}
Since the powers of
are
it follows that
and
have the same last
digit for
. Similarily,
and
have the same last digit. (This follows as
too).
The expression then has the same last digit as
which is just
.