2023 AMC 8 Problems/Problem 16: Difference between revisions

Revision as of 01:08, 25 January 2023

Problem

The letters P, Q, and R are entered into a $20\times20$ table according to the pattern shown below. How many Ps, Qs, and Rs will appear in the completed table?

$%%Table made by Technodoggo \begin{array}[b]{|c|c|c|c|c|c} \vdots &\vdots&\vdots&\vdots&\vdots&\iddots\\\hline Q&R&P&Q&R&\cdots\\\hline P&Q&R&P&Q&\cdots\\\hline R&P&Q&R&P&\cdots\\\hline Q&R&P&Q&R&\cdots\\\hline P&Q&R&P&Q&\cdots\\\hline \end{array}$

$\textbf{(A)}~132\text{ Ps, }134\text{ Qs, }134\text{ Rs}$

$\textbf{(B)}~133\text{ Ps, }133\text{ Qs, }134\text{ Rs}$

$\textbf{(C)}~133\text{ Ps, }134\text{ Qs, }133\text{ Rs}$

$\textbf{(D)}~134\text{ Ps, }132\text{ Qs, }134\text{ Rs}$

$\textbf{(E)}~134\text{ Ps, }133\text{ Qs, }133\text{ Rs}$

Solution 1

In our $5 \times 5$ grid we can see there are $8$ , $9$ and $8$ of the letters P, Q and R’s respectively. We can see our pattern between each is $x$ , $x+1$ , $x$ for the P, Q and R’s respectively. This such pattern will follow in our bigger example, so we can see that the only answer choice which satisfies this condition is $\boxed{\text{(C)}\hspace{0.1 in} 133, 134, 133}$

(Note: you could also "cheese" this problem by listing out all of the letters horizontally in a single line and looking at the repeating pattern.)

~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat

Animated Video Solution

https://youtu.be/1tnMR0lNEFY

~Star League (https://starleague.us)

Video Solution by OmegaLearn (Using Cyclic Patterns)

https://youtu.be/83FnFhe4QgQ

2023 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 15	Followed by Problem 17
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing

@@ Line 14: / Line 14: @@
-<math>\boxed{\text{A}}~132\text{ Ps, }134\text{ Qs, }134\text{ Rs}</math>
+<math>\textbf{(A)}~132\text{ Ps, }134\text{ Qs, }134\text{ Rs}</math>
-<math>\boxed{\text{B}}~133\text{ Ps, }133\text{ Qs, }134\text{ Rs}</math>
-<math>\boxed{\text{C}}~133\text{ Ps, }134\text{ Qs, }133\text{ Rs}</math>
+<math>\textbf{(B)}~133\text{ Ps, }133\text{ Qs, }134\text{ Rs}</math>
-<math>\boxed{\text{D}}~134\text{ Ps, }132\text{ Qs, }134\text{ Rs}</math>
-<math>\boxed{\text{E}}~134\text{ Ps, }133\text{ Qs, }133\text{ Rs}</math>
+<math>\textbf{(C)}~133\text{ Ps, }134\text{ Qs, }133\text{ Rs}</math>
+<math>\textbf{(D)}~134\text{ Ps, }132\text{ Qs, }134\text{ Rs}</math>
+<math>\textbf{(E)}~134\text{ Ps, }133\text{ Qs, }133\text{ Rs}</math>
 == Solution 1 ==

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