2023 AMC 8 Problems/Problem 24: Difference between revisions
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==Problem== | |||
Isosceles <math>\triangle ABC</math> has equal side lengths <math>AB</math> and <math>BC</math>. In the figure below, segments are drawn parallel to <math>\overline{AC}</math> so that the shaded portions of <math>\triangle ABC</math> have the same area. The heights of the two unshaded portions are 11 and 5 units, respectively. What is the height of <math>h</math> of <math>\triangle ABC</math>? | |||
*Add asymptote diagram* | |||
<cmath>\textbf{(A) } 14.6 \qquad \textbf{(B) } 14.8 \qquad \textbf{(C) } 15 \qquad \textbf{(D) } 15.2 \qquad \textbf{(E) } ~15.4</cmath> | |||
\end{exx} | |||
==Video Solution== | |||
https://youtu.be/almtw4n-92A | |||
Revision as of 18:22, 24 January 2023
Problem
Isosceles 
has equal side lengths 
and 
. In the figure below, segments are drawn parallel to 
so that the shaded portions of have the same area. The heights of the two unshaded portions are 11 and 5 units, respectively. What is the height of 
of ?
- Add asymptote diagram*
![\[\textbf{(A) } 14.6 \qquad \textbf{(B) } 14.8 \qquad \textbf{(C) } 15 \qquad \textbf{(D) } 15.2 \qquad \textbf{(E) } ~15.4\]](http://latex.artofproblemsolving.com/7/4/2/742d88a5dc4c08ac16691b9d218f5fc6a0ea8a31.png)
\end{exx}
