2022 AMC 8 Problems/Problem 7: Difference between revisions
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<math>\textbf{(A) } 0.6 \qquad \textbf{(B) } 10 \qquad \textbf{(C) } 1800 \qquad \textbf{(D) } 7200 \qquad \textbf{(E) } 36000</math> | <math>\textbf{(A) } 0.6 \qquad \textbf{(B) } 10 \qquad \textbf{(C) } 1800 \qquad \textbf{(D) } 7200 \qquad \textbf{(E) } 36000</math> | ||
==Solution== | ==Solution 1== | ||
Notice that the number of kilobits in this song is <math>4.2 \cdot 8000 = 8 \cdot 7 \cdot 6 \cdot 100.</math> | Notice that the number of kilobits in this song is <math>4.2 \cdot 8000 = 8 \cdot 7 \cdot 6 \cdot 100.</math> | ||
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Finally, we divide this number by <math>60</math> because this is the number of <i><b>seconds</b></i> to get the answer <math>\frac{600}{60}=\boxed{\textbf{(B) } 10}.</math> | Finally, we divide this number by <math>60</math> because this is the number of <i><b>seconds</b></i> to get the answer <math>\frac{600}{60}=\boxed{\textbf{(B) } 10}.</math> | ||
~wamofan | ~wamofan | ||
==Solution 2 (Dimensional Analysis)== | |||
We seek a value of <math>x</math> that makes the following equation true, since evrery other quantity equals <math>1</math>. | |||
<cmath>\frac{x\ \text{min}}{4.2\ \text{mb}} \cdot \frac{56\ \text{kb}}{1\ \text{sec}} \cdot \frac{1\ \text{mb}}{8000\ \text{kb}} \cdot \frac{60\ \text{sec}}{1\ \text{min}} = 1</cmath> | |||
Solving yields <math>x=\boxed{\textbf{(B) } 10}</math> | |||
==Video Solution== | ==Video Solution== | ||
https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=475 | https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=475 | ||
Revision as of 08:41, 9 December 2022
Problem
When the World Wide Web first became popular in the 
s, download speeds reached a maximum of about 
kilobits per second. Approximately how many minutes would the download of a 
-megabyte song have taken at that speed? (Note that there are 
kilobits in a megabyte.)
Solution 1
Notice that the number of kilobits in this song is 
We must divide this by in order to find out how many seconds this song would take to download: 
Finally, we divide this number by 
because this is the number of seconds to get the answer 
~wamofan
Solution 2 (Dimensional Analysis)
We seek a value of 
that makes the following equation true, since evrery other quantity equals 
.
![\[\frac{x\ \text{min}}{4.2\ \text{mb}} \cdot \frac{56\ \text{kb}}{1\ \text{sec}} \cdot \frac{1\ \text{mb}}{8000\ \text{kb}} \cdot \frac{60\ \text{sec}}{1\ \text{min}} = 1\]](http://latex.artofproblemsolving.com/7/8/2/782716c86ca6dbea18b3024b655c764eb5c01281.png)
Solving yields 
Video Solution
https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=475
~Interstigation
See Also
| 2022 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 6 |
Followed by Problem 8 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: Unable to save thumbnail to destination
