Art of Problem Solving

2022 AMC 10B Problems/Problem 1: Difference between revisions

Mrthinker (talk | contribs)
Mrthinker (talk | contribs)
Blanked the page
Tag: Blanking
Line 1: Line 1:
==Problem==
A donkey suffers an attack of hiccups and the first hiccup happens at <math>4:00</math> one afternoon. Suppose that
the donkey hiccups regularly every <math>5</math> seconds. At what time does the donkey’s <math>700</math>th hiccup occur?


<math>\textbf{(A) }15 \text{ seconds after } 4:58</math>
<math>\textbf{(B) }20 \text{ seconds after } 4:58</math>
<math>\textbf{(C) }25 \text{ seconds after } 4:58</math>
<math>\textbf{(D) }30 \text{ seconds after } 4:58</math>
<math>\textbf{(E) }35 \text{ seconds after } 4:58</math>
==Solution==
Since the donkey hiccupped the 1st hiccup at <math>4:00</math>, he hiccupped for <math>5 \cdot (700-1) = 3495</math> seconds, which is <math>58</math> minutes and <math>15</math> seconds, so the answer is <math>\boxed{\textbf{(A) }15 \text{ seconds after } 4:58}</math>.
~MrThinker
== See Also ==
{{AMC10 box|year=2022|ab=B|num-b=7|num-a=3}}
{{AMC12 box|year=2022|ab=B|num-b=5|num-a=5}}
{{MAA Notice}}

Revision as of 13:43, 17 November 2022