2007 AMC 10B Problems/Problem 2: Difference between revisions

Latest revision as of 09:33, 7 March 2022

Problem

Define the operation $\star$ by $a \star b = (a+b)b.$ What is $(3 \star 5) - (5 \star 3)?$

$\textbf{(A) } -16 \qquad\textbf{(B) } -8 \qquad\textbf{(C) } 0 \qquad\textbf{(D) } 8 \qquad\textbf{(E) } 16$

Solution 1

Substitute and simplify. $(3+5)5 - (5+3)3 = (3+5)2 = 8\cdot2 = \boxed{\textbf{(E) }16}$

Solution 2

Note that $(a \star b) - (b \star a) = (a+b)b - (b+a)a= (a+b)(b-a)= b^2 - a^2$ . We can substitute $a=3$ and $b=5$ to get $5^2 - 3^2 = \boxed{\textbf{(E) }16}$ .

~MathFun1000 (Minor Edits)

2007 AMC 10B (Problems • Answer Key • Resources)
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@@ Line 8: / Line 8: @@
 Substitute and simplify.
-<cmath>(3+5)5 - (5+3)3 = (3+5)2 = (8)2 = \boxed{\textbf{(E) }16}</cmath>
+<cmath>(3+5)5 - (5+3)3 = (3+5)2 = 8\cdot2 = \boxed{\textbf{(E) }16}</cmath>
 ==Solution 2==

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2007 AMC 10B Problems/Problem 2: Difference between revisions

Latest revision as of 09:33, 7 March 2022

Contents

Problem

Solution 1

Solution 2

See Also