2002 AMC 8 Problems/Problem 14: Difference between revisions
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==Solution== | ==Solution== | ||
Let's assume that each item is <math>100</math> dollars. First we take off <math>30\%</math> off of <math>100</math> dollars. <math>100\cdot0.7=70</math> | Let's assume that each item is <math>100</math> dollars. First we take off <math>30\%</math> off of <math>100</math> dollars. <math>100\cdot0.7=70</math> | ||
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So the final price of an item is \$56. We have to do <math>100-56</math> because <math>56</math> was the final price and we wanted the discount. So the final answer is <math>44\%</math>, which is answer choice <math>B</math>. | So the final price of an item is \$56. We have to do <math>100-56</math> because <math>56</math> was the final price and we wanted the discount. So the final answer is <math>44\%</math>, which is answer choice <math>B</math>. | ||
==Video Solution== | |||
https://youtu.be/DUqszaQ01lM Soo, DRMS, NM | |||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2002|num-b=13|num-a=15}} | {{AMC8 box|year=2002|num-b=13|num-a=15}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 01:32, 7 March 2022
Problem
A merchant offers a large group of items at
off. Later, the merchant takes
off these sale prices and claims that the final price of these items is
off the original price. The total discount is
Solution
Let's assume that each item is
dollars. First we take off
off of
dollars.
Next, we take off the extra
as asked by the problem.
So the final price of an item is \$56. We have to do
because
was the final price and we wanted the discount. So the final answer is
, which is answer choice
.
Video Solution
https://youtu.be/DUqszaQ01lM Soo, DRMS, NM
See Also
| 2002 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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