2010 AMC 8 Problems/Problem 6: Difference between revisions
| Line 13: | Line 13: | ||
==Solution== | ==Solution== | ||
An equilateral triangle has | An equilateral triangle has 3 lines of symmetry. | ||
A non-square rhombus has | A non-square rhombus has 2 lines of symmetry. | ||
A non-square rectangle has | A non-square rectangle has 2 lines of symmetry. | ||
An isosceles trapezoid has | An isosceles trapezoid has 1 line of symmetry. | ||
A square has | A square has 4 lines of symmetry. | ||
so the answer is E | |||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2010|num-b=5|num-a=7}} | {{AMC8 box|year=2010|num-b=5|num-a=7}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 12:38, 15 August 2021
Problem
Which of the following figures has the greatest number of lines of symmetry?
Solution
An equilateral triangle has 3 lines of symmetry. A non-square rhombus has 2 lines of symmetry. A non-square rectangle has 2 lines of symmetry. An isosceles trapezoid has 1 line of symmetry. A square has 4 lines of symmetry.
so the answer is E
See Also
| 2010 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing
