2004 AMC 8 Problems/Problem 24: Difference between revisions
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==Problem== | ==Problem== | ||
In the figure, <math>ABCD</math> is a rectangle and <math>EFGH</math> is a parallelogram. Using the measurements given in the figure, what is the length <math>d</math> of the segment that is perpendicular to <math>\overline{HE}</math> and <math>\overline{FG}</math>? | In the figure, <math>ABCD</math> is a rectangle and <math>EFGH</math> is a parallelogram. Using the measurements given in the figure, what is the length <math>d</math> of the segment that is perpendicular(altitude of parallelogram <math>EFGH</math>) to <math>\overline{HE}</math> and <math>\overline{FG}</math>? | ||
<asy> | <asy> | ||
Revision as of 16:21, 25 July 2021
Problem
In the figure,
is a rectangle and
is a parallelogram. Using the measurements given in the figure, what is the length
of the segment that is perpendicular(altitude of parallelogram
) to
and
?
Solution
The area of the parallelogram can be found in two ways. The first is by taking rectangle
and subtracting the areas of the triangles cut out to create parallelogram
. This is
The second way is by multiplying the base of the parallelogram such as
with its altitude
, which is perpendicular to both bases.
is a
triangle so
. Set these two representations of the area together.
See Also
| 2004 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 23 |
Followed by Problem 25 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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