2021 AMC 10B Problems/Problem 7: Difference between revisions
MRENTHUSIASM (talk | contribs) Added in Solution 2, and changed $l$ to $\ell$ for better writing purposes. |
MRENTHUSIASM (talk | contribs) m →Solution 2 (Explains Solution 1 Using Intuition): Emphasizes Solution 1's diagram. Minor edit. |
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2. To maximize the area of the desired region, we draw the circle with radius <math>5</math> south to <math>\ell.</math> | 2. To maximize the area of the desired region, we draw the circle with radius <math>5</math> south to <math>\ell.</math> | ||
3. Now, we need to subtract out the circle with radius <math>3</math> <b>at least</b>. The optimal situation is that the circle with radius <math>3</math> encompasses the circle with radius <math>1,</math> so that we do not need to subtract more. That is, the two smallest circles are on the same side of <math>\ell,</math> but can be on either side. | 3. Now, we need to subtract out the circle with radius <math>3</math> <b>at least</b>. The optimal situation is that the circle with radius <math>3</math> encompasses the circle with radius <math>1,</math> so that we do not need to subtract more. That is, the two smallest circles are on the same side of <math>\ell,</math> but can be on either side. The diagram in Solution 1 shows one possible positions of the four circles. | ||
Together, the answer is <math>7^2\pi+5^2\pi-3^2\pi=\boxed{\textbf{(D) }65\pi}.</math> | Together, the answer is <math>7^2\pi+5^2\pi-3^2\pi=\boxed{\textbf{(D) }65\pi}.</math> | ||
Revision as of 12:32, 5 March 2021
Problem
In a plane, four circles with radii 
and 
are tangent to line 
at the same point 
but they may be on either side of . Region 
consists of all the points that lie inside exactly one of the four circles. What is the maximum possible area of region ?
Solution 1
![[asy] /* diagram made by samrocksnature */ pair A=(10,0); pair B=(-10,0); draw(A--B); draw(circle((0,-1),1)); draw(circle((0,-3),3)); draw(circle((0,-5),5)); draw(circle((0,7),7)); dot((0,7)); draw((0,7)--(0,0)); label("$7$",(0,3.5),E); label("$\ell$",(-9,0),S); [/asy]](http://latex.artofproblemsolving.com/f/2/d/f2dc15b29ae722b2da5d59c2b7cc359f8b84cf6c.png)
After a bit of wishful thinking and inspection, we find that the above configuration maximizes our area, which is 
~ samrocksnature
Solution 2 (Explains Solution 1 Using Intuition)
Suppose each circle lies north or south to line 
We construct the circles one by one:
1. Without the loss of generality, we draw the circle with radius north to
2. To maximize the area of the desired region, we draw the circle with radius 
south to
3. Now, we need to subtract out the circle with radius 
at least. The optimal situation is that the circle with radius encompasses the circle with radius 
so that we do not need to subtract more. That is, the two smallest circles are on the same side of 
but can be on either side. The diagram in Solution 1 shows one possible positions of the four circles.
Together, the answer is 
~MRENTHUSIASM
Video Solution by OmegaLearn (Area of Circles and Logic)
~ pi_is_3.14
Video Solution by TheBeautyofMath
https://youtu.be/GYpAm8v1h-U?t=206
~IceMatrix
Video Solution by Interstigation
https://youtu.be/DvpN56Ob6Zw?t=555
~Interstigation
See Also
| 2021 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 6 |
Followed by Problem 8 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
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