2008 AMC 12B Problems/Problem 6: Difference between revisions
No edit summary |
|||
| Line 7: | Line 7: | ||
==Solution== | ==Solution== | ||
Every time the pedometer flips, Pete has walked <math>100,000</math> steps. Therefore, Pete has walked a total of <math>100,000 * 44 + 50,000 = 4,450,000</math> steps, which is <math>4,450,000/1,800 = 2472.2</math> miles, which is closest to answer choice <math>\boxed{A}</math>. | Every time the pedometer flips, Pete has walked <math>100,000</math> steps. Therefore, Pete has walked a total of <math>100,000 * 44 + 50,000 = 4,450,000</math> steps, which is <math>4,450,000/1,800 = 2472.2</math> miles, which is the closest to the answer choice <math>\boxed{A}</math>. | ||
==See Also== | ==See Also== | ||
Revision as of 13:17, 16 February 2021
Problem
Postman Pete has a pedometer to count his steps. The pedometer records up to 
steps, then flips over to 
on the next step. Pete plans to determine his mileage for a year. On January 
Pete sets the pedometer to . During the year, the pedometer flips from to forty-four times. On December 
the pedometer reads 
. Pete takes 
steps per mile. Which of the following is closest to the number of miles Pete walked during the year?
Solution
Every time the pedometer flips, Pete has walked 
steps. Therefore, Pete has walked a total of 
steps, which is 
miles, which is the closest to the answer choice 
.
See Also
| 2008 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 5 |
Followed by Problem 7 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing
