1978 AHSME Problems/Problem 14: Difference between revisions
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== Problem 14 == | |||
If an integer <math>n > 8</math> is a solution of the equation <math>x^2 - ax+b=0</math> and the representation of <math>a</math> in the base-<math>n</math> number system is <math>18</math>, | |||
then the base-n representation of <math>b</math> is | |||
<math>\textbf{(A)}\ 18 \qquad | |||
\textbf{(B)}\ 20 \qquad | |||
\textbf{(C)}\ 80 \qquad | |||
\textbf{(D)}\ 81 \qquad | |||
\textbf{(E)}\ 280 </math> | |||
== Solution == | |||
Assuming the solutions to the equation are n and m, by Vieta's formulas, <math>n_n + m_n = 18_n</math>. | Assuming the solutions to the equation are n and m, by Vieta's formulas, <math>n_n + m_n = 18_n</math>. | ||
| Line 11: | Line 21: | ||
The answer is (C) <math>80</math> | The answer is (C) <math>80</math> | ||
==See Also== | |||
{{AHSME box|year=1978|num-b=13|num-a=15}} | |||
{{MAA Notice}} | |||
Latest revision as of 20:08, 13 February 2021
Problem 14
If an integer
is a solution of the equation
and the representation of
in the base-
number system is
,
then the base-n representation of
is
Solution
Assuming the solutions to the equation are n and m, by Vieta's formulas,
.
, so
.
.
Also by Vieta's formulas,
.
.
The answer is (C)
See Also
| 1978 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: Unable to save thumbnail to destination