2020 AMC 8 Problems/Problem 2: Difference between revisions

Revision as of 13:15, 3 January 2021

Problem

Four friends do yardwork for their neighbors over the weekend, earning $\$15, \$20, \$25,$ and $\$40,$ respectively. They decide to split their earnings equally among themselves. In total how much will the friend who earned $\$40$ give to the others?

$\textbf{(A) }\$5 \qquad \textbf{(B) }\$10 \qquad \textbf{(C) }\$15 \qquad \textbf{(D) }\$20 \qquad \textbf{(E) }\$25$

Solution

The friends earn $\$\left(15+20+25+40\right)=\$100$ in total. Since they decided to split their earnings equally, it follows that each person will get $\$\left(\frac{100}{4}\right)=\$25$ . Since the friend who earned $\$40$ will need to leave with $\$25$ , he will have to give $\$\left(40-25\right)=\boxed{\textbf{(C) }\$15}$ to the others.

Video Solution

https://youtu.be/SPNobOd4t1c (Channel also has resources to prepare for your AIME qualification)

https://youtu.be/eSxzI8P9_h8

2020 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 3
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All AJHSME/AMC 8 Problems and Solutions

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2020 AMC 8 Problems/Problem 2: Difference between revisions

Revision as of 13:15, 3 January 2021

Contents

Problem

Solution

Video Solution

See also

@@ Line 8: / Line 8: @@
 ==Video Solution==
+https://youtu.be/SPNobOd4t1c (Channel also has resources to prepare for your AIME qualification)
 https://youtu.be/eSxzI8P9_h8