2018 AMC 10B Problems/Problem 1: Difference between revisions
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Problem: | |||
Suppose we write down the smallest (positive) <math>2</math>-digit, <math>3</math>-digit, and <math>4</math>-digit multiples of <math>8</math>. | |||
== Solution 1 == | == Solution 1 == | ||
Revision as of 18:43, 22 December 2020
Problem:
Suppose we write down the smallest (positive) 
-digit, 
-digit, and 
-digit multiples of 
.
Solution 1
The area of the pan is 
= 
. Since the area of each piece is , there are 
pieces. Thus, the answer is 
.
Solution 2
By dividing each of the dimensions by , we get a 
grid which makes 
pieces. Thus, the answer is .
Video Solution
~savannahsolver
See Also
| 2018 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
| 2018 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by First Problem |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
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