Talk:2020 AMC 8 Problems/Problem 8: Difference between revisions

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	~~== Solution 3 ==~~

	The smallest amount of money (in cents) that Ricardo can have is <math>2019</math> pennies and <math>1</math> nickel, which is equal to <math>2019 \cdot 1 + 1 \cdot 5 = 2024</math> cents. Similarly, the largest amount of money he can have is <math>1</math> penny and <math>2019</math> nickels, which is equal to <math>1 \cdot 1 + 2019 \cdot 5 = 10096</math> cents. So, the answer is <math>10096 - 2024 = \boxed{\textbf{(C) }8072}</math>

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