2020 AMC 8 Problems/Problem 15: Difference between revisions
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==Problem 15== | |||
Suppose <math>15\%</math> of <math>x</math> equals <math>20\%</math> of <math>y.</math> What percentage of <math>x</math> is <math>y?</math> | Suppose <math>15\%</math> of <math>x</math> equals <math>20\%</math> of <math>y.</math> What percentage of <math>x</math> is <math>y?</math> | ||
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==Solution 1== | ==Solution 1== | ||
We set up the following equation based on the given information: <cmath>\frac{15x}{100}=\frac{20y}{100}</cmath> Solving for <math>x</math> yields <cmath>\frac{3x}{20}=\frac{y}{5}</cmath> <cmath>20y=15x</cmath> <cmath>x=1.\overline{3}y ==> D</cmath> | |||
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Revision as of 00:21, 18 November 2020
Problem 15
Suppose
of
equals
of
What percentage of
is
Solution 1
We set up the following equation based on the given information:
Solving for
yields