2001 AMC 8 Problems/Problem 12: Difference between revisions

Revision as of 05:47, 9 November 2020

If $a\otimes b = \dfrac{a + b}{a - b}$ , then $(6\otimes 4)\otimes 3 =$

$\text{(A)}\ 4 \qquad \text{(B)}\ 13 \qquad \text{(C)}\ 15 \qquad \text{(D)}\ 30 \qquad \text{(E)}\ 72$

$6\otimes4=\frac{6+4}{6-4}=5$ . $5\otimes3=\frac{5+3}{5-3}=4, \boxed{\text{A}}$

2001 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 11	Followed by Problem 13
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All AJHSME/AMC 8 Problems and Solutions

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 ==See Also==
 {{AMC8 box|year=2001|num-b=11|num-a=13}}
 {{MAA Notice}}