1986 AIME Problems/Problem 8: Difference between revisions
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== Problem == | == Problem == | ||
Let <math>\displaystyle S</math> be the sum of the base <math>\displaystyle 10</math> logarithms of all the proper divisors of <math>\displaystyle 1000000</math>. What is the integer nearest to <math>\displaystyle S</math>? | |||
== Solution == | == Solution == | ||
{{solution}} | |||
== See also == | == See also == | ||
Revision as of 19:04, 10 February 2007
Problem
Let 
be the sum of the base 
logarithms of all the proper divisors of 
. What is the integer nearest to ?
Solution
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See also
| 1986 AIME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
