1978 AHSME Problems/Problem 1: Difference between revisions
| Line 16: | Line 16: | ||
Multiplying each side by <math>x^2</math>, we get <math>x^2-4x+4 = 0</math>. Factoring, we get <math>(x-2)(x-2) = 0</math>. Therefore, <math>x = 2</math>. | Multiplying each side by <math>x^2</math>, we get <math>x^2-4x+4 = 0</math>. Factoring, we get <math>(x-2)(x-2) = 0</math>. Therefore, <math>x = 2</math>. | ||
<math>\frac{2}{x} = \boxed{\textbf{(B) }1}</math> | <math>\frac{2}{x} = \boxed{\textbf{(B) }1}</math> | ||
~awin | |||
Revision as of 14:26, 20 January 2020
Problem 1
If 
, then 
equals
Solution 1
By guessing and checking, 2 works.
Solution 2
Multiplying each side by 
, we get 
. Factoring, we get 
. Therefore, 
.
~awin
