2012 AMC 10B Problems/Problem 19: Difference between revisions
| Line 26: | Line 26: | ||
label("C",(30,0),E); | label("C",(30,0),E); | ||
label("D",(30,6),NE); | label("D",(30,6),NE); | ||
label("G",(15,6),N); | |||
label("E",(0,-2),SW); | |||
label("F",(15/2,0),N); | |||
draw(A--B); | draw(A--B); | ||
draw(B--C); | draw(B--C); | ||
draw(C--D); | draw(C--D); | ||
draw(D--A); | draw(D--A); | ||
draw(E--D); | |||
</asy> | </asy> | ||
Revision as of 13:56, 31 December 2019
Problem
In rectangle
,
,
, and
is the midpoint of
. Segment
is extended 2 units beyond
to point
, and
is the intersection of
and
. What is the area of
?
Solution
Note that the area of
equals the area of
.
Since
. Now,
, so
and
so
Therefore,
hence our answer is
See Also
| 2012 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 18 |
Followed by Problem 20 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
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