2019 AMC 8 Problems/Problem 7: Difference between revisions
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148</math> points in her <math>2</math> tests. So the minimum score she can get is when one of her <math>2</math> scores is <math>100</math>. So the least possible score she can get is <math>\boxed{\textbf{(A)}\ 48}</math>. | 148</math> points in her <math>2</math> tests. So the minimum score she can get is when one of her <math>2</math> scores is <math>100</math>. So the least possible score she can get is <math>\boxed{\textbf{(A)}\ 48}</math>. | ||
~heeeeeeeheeeeee | ~heeeeeeeheeeeee | ||
Note: You can verify that | Note: You can verify that <math>\boxed{48}</math> is the right answer because it is the lowest answer out of the 5. Since it is possible to get 48, we are guaranteed that that is the right answer. | ||
~~ gorefeebuddie | ~~ gorefeebuddie | ||
Revision as of 19:29, 24 November 2019
Problem 7
Shauna takes five tests, each worth a maximum of
points. Her scores on the first three tests are
,
, and
. In order to average
for all five tests, what is the lowest score she could earn on one of the other two tests?
Solution 1
Right now, she scored
and
points, with a total of
points. She wants her average to be
for her
tests so she needs to score
points in total. She needs to score a total of
points in her
tests. So the minimum score she can get is when one of her
scores is
. So the least possible score she can get is
.
~heeeeeeeheeeeee
Note: You can verify that
is the right answer because it is the lowest answer out of the 5. Since it is possible to get 48, we are guaranteed that that is the right answer.
~~ gorefeebuddie
See Also
| 2019 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 6 |
Followed by Problem 8 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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