2019 AMC 8 Problems/Problem 13: Difference between revisions
Phoenixfire (talk | contribs) |
|||
| Line 8: | Line 8: | ||
~heeeeeeheeeee | ~heeeeeeheeeee | ||
==Solution 2== | ==Solution 2== | ||
Revision as of 12:08, 22 November 2019
Problem 13
A palindrome is a number that has the same value when read from left to right or from right to left. (For example 12321 is a palindrome.) Let
be the least three-digit integer which is not a palindrome but which is the sum of three distinct two-digit palindromes. What is the sum of the digits of
?
Solution 1
All the two digit palindromes are multiples of 11. The least 3 digit integer that is the sum of 3 two digit palindromes is a multiple of 11. The least 3 digit multiple of 11 is 110. The sum of the digits of 110 is 1 + 1 + 0 =
.
~heeeeeeheeeee
Solution 2
We let the two digit palindromes be
,
, and
, which sum to
. Now, we can let
. This means we are looking for the smallest
such that
and
is not a palindrome. Thus, we test
for
, which works so
, meaning that the sum requested is
.
~smartninja2000
See Also
| 2019 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 12 |
Followed by Problem 14 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing