2006 AMC 12A Problems/Problem 12: Difference between revisions
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== Problem == | == Problem == | ||
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A number of linked rings, each 1 cm thick, are hanging on a peg. The top ring has an outisde diameter of 20 cm. The outside diameter of each of the outer rings is 1 cm less than that of the ring above it. The bottom ring has an outside diameter of 3 cm. What is the distance, in cm, from the top of the top ring to the bottom of the bottom ring? | |||
<math> \mathrm{(A) \ } 171\qquad \mathrm{(B) \ } 173\qquad \mathrm{(C) \ } 182\qquad \mathrm{(D) \ } 188</math><math>\mathrm{(E) \ } 210</math> | |||
== Solution == | |||
[[ | == See also == | ||
[[ | * [[2006 AMC 12A Problems]] | ||
*[[2006 AMC 12A Problems/Problem 11|Previous Problem]] | |||
*[[2006 AMC 12A Problems/Problem 13|Next Problem]] | |||
Revision as of 17:52, 5 November 2006
Problem
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A number of linked rings, each 1 cm thick, are hanging on a peg. The top ring has an outisde diameter of 20 cm. The outside diameter of each of the outer rings is 1 cm less than that of the ring above it. The bottom ring has an outside diameter of 3 cm. What is the distance, in cm, from the top of the top ring to the bottom of the bottom ring?
