Art of Problem Solving
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1964 AHSME Problems/Problem 30: Difference between revisions

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Created page with "==Problem== The larger root minus the smaller root of the equation <cmath>(7+4\sqrt{3})x^2+(2+\sqrt{3})x-2=0</cmath> is <math>\textbf{(A) }-2+3\sqrt{3}\qquad\textbf{(B) }2-\sq..."
 
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<math>\textbf{(A) }-2+3\sqrt{3}\qquad\textbf{(B) }2-\sqrt{3}\qquad\textbf{(C) }6+3\sqrt{3}\qquad\textbf{(D) }6-3\sqrt{3}\qquad \textbf{(E) }3\sqrt{3}+2</math>
<math>\textbf{(A) }-2+3\sqrt{3}\qquad\textbf{(B) }2-\sqrt{3}\qquad\textbf{(C) }6+3\sqrt{3}\qquad\textbf{(D) }6-3\sqrt{3}\qquad \textbf{(E) }3\sqrt{3}+2</math>
==See Also==
{{AHSME 40p box|year=1964|num-b=29|num-a=31}}
[[Category:Introductory Algebra Problems]]
{{MAA Notice}}

Revision as of 22:15, 24 July 2019

Problem

The larger root minus the smaller root of the equation \[(7+4\sqrt{3})x^2+(2+\sqrt{3})x-2=0\] is

$\textbf{(A) }-2+3\sqrt{3}\qquad\textbf{(B) }2-\sqrt{3}\qquad\textbf{(C) }6+3\sqrt{3}\qquad\textbf{(D) }6-3\sqrt{3}\qquad \textbf{(E) }3\sqrt{3}+2$


See Also

1964 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 29
Followed by
Problem 31
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
All AHSME Problems and Solutions

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