2003 AMC 10B Problems/Problem 11: Difference between revisions

Revision as of 08:01, 6 July 2019

A line with slope $3$ intersects a line with slope $5$ at point $(10,15)$ . What is the distance between the $x$ -intercepts of these two lines?

$\textbf{(A) } 2 \qquad\textbf{(B) } 5 \qquad\textbf{(C) } 7 \qquad\textbf{(D) } 12 \qquad\textbf{(E) } 20$

Using the point-slope form, the equation of each line is

$y-15=3(x-10) \longrightarrow y=3x-15$ $y-15=5(x-10) \longrightarrow y=5x-35$

Substitute in $y=0$ to find the $x$ -intercepts.

$0=3x-15\longrightarrow x=5$ $0=5x-35\longrightarrow x=7$ The difference between them is $7-5=\boxed{\textbf{(A) \ } 2}$ .

2003 AMC 10B (Problems • Answer Key • Resources)
Preceded by Problem 10	Followed by Problem 12
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 10 Problems and Solutions

@@ Line 7: / Line 7: @@
 ==Solution==
-Using the point-slope formula, the equation of each line is
+Using the point-slope form, the equation of each line is
 <cmath>y-15=3(x-10) \longrightarrow y=3x-15</cmath>