1959 AHSME Problems/Problem 38: Difference between revisions

Revision as of 15:22, 3 March 2019

Subtract 4x from both sides so you get: $\sqrt{2x}=1-4x$

Then just square and simplify to get: $x=\frac{1}{8}$

This is answer choice B.

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-If <math>4x+\sqrt{2x}=1</math>, then <math>x</math>
+Subtract 4x from both sides so you get:
+<math>\sqrt{2x}=1-4x</math>
+Then just square and simplify to get:
+<math>x=\frac{1}{8}</math>
-(A) is an integer
+This is answer choice B.
-(B) is fractional
-(C) is irrational
-(D) is imaginary
-(E) may have two different values